1864 United States presidential election in Michigan
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Elections in Michigan |
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The 1864 United States presidential election in Michigan took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose eight[1] representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Michigan was won by incumbent president Abraham Lincoln over Democratic challenger George B. McClellan by a margin of 7.2%.[2]
As of the 2020 presidential election[update], this is the last time Ottawa County voted for a Democratic Presidential candidate.[3]
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
National Union | Abraham Lincoln (incumbent) | 79,149 | 53.60% | |
Democratic | George B. McClellan | 68,513 | 46.40% | |
Total votes | 147,662 | 100% |
See also
References
- ^ "1864 Election for the Twentieth Term (1865-1869)". Retrieved 2018-11-28.
- ^ a b c "1864 Presidential General Election Results - Michigan".
- ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 222-227 ISBN 0786422173
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